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题目链接: https://leetcode.com/problems/logger-rate-limiter/

Design a logger system that receive stream of messages along with its timestamps, each message should be printed if and only if it is not printed in the last 10 seconds.

Given a message and a timestamp (in seconds granularity), return true if the message should be printed in the given timestamp, otherwise returns false.

It is possible that several messages arrive roughly at the same time.

Example:

Logger logger = new Logger();// logging string "foo" at timestamp 1logger.shouldPrintMessage(1, "foo"); returns true; // logging string "bar" at timestamp 2logger.shouldPrintMessage(2,"bar"); returns true;// logging string "foo" at timestamp 3logger.shouldPrintMessage(3,"foo"); returns false;// logging string "bar" at timestamp 8logger.shouldPrintMessage(8,"bar"); returns false;// logging string "foo" at timestamp 10logger.shouldPrintMessage(10,"foo"); returns false;// logging string "foo" at timestamp 11logger.shouldPrintMessage(11,"foo"); returns true;

思路: 啰嗦了那么多都没用, 一个hash表就可以搞定.

代码如下:

class Logger {public:    /** Initialize your data structure here. */    Logger() {            }        /** Returns true if the message should be printed in the given timestamp, otherwise returns false.        If this method returns false, the message will not be printed.        The timestamp is in seconds granularity. */    bool shouldPrintMessage(int timestamp, string message) {        if(hash.count(message) == 0 || timestamp -hash[message] >= 10)        {            hash[message] = timestamp;            return true;        }        return false;    }private:    unordered_map
   
     hash;};/** * Your Logger object will be instantiated and called as such: * Logger obj = new Logger(); * bool param_1 = obj.shouldPrintMessage(timestamp,message); */
   

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